Question 373975
{{{y^2=(3/4)y+4/7}}}
{{{y^2-(3/4)y-4/7=0}}}
Use the discriminant, {{{D}}}
{{{D=b^2-4ac}}}
{{{D=(3/4)^2-4(1)(-4/7)}}}
{{{D=9/16+16/7}}}
Since {{{D>0}}}, there are two real roots.
Since {{{D}}} is not a perfect square, the two roots are irrational.
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