Question 373936
<pre>
{{{2^(3x-4)=5}}}

Take logs of both sides:

{{{log((2^(3x-4)))=log((5))}}}

Use the principle of logarithms:  {{{log(B,(A^C))=C*log(B,(A))}}} on the left side

{{{(3x-4)log((2))=log((5))}}}

Divide both sides by {{{log(2)}}}

{{{(3x-4)log((2))/log((2))}}}{{{""=""}}}{{{log((5))/log((2))}}}

{{{3x-4}}}{{{""=""}}}{{{log((5))/log((2))}}}

Get a calculator and do the right side:


{{{3x-4=2.321928095}}}

Add 4 to both sides

{{{3x=6.321928095}}}

Divide both sides by 3

{{{3x/3=6.321928095/3}}}

{{{cross(3)x/cross(3)=6.321928095/3}}}

{{{x=6.321928095/3}}}

{{{x=2.107309365}}}

Edwin</pre>