Question 373909
{{{6x -4y = 13 + y}}}
{{{-5y = -6x+13 }}}
{{{y=(6/5)x-13/5}}}
Perpendicular lines have slopes that are negative reciprocals,
{{{m[1]*m[2]=-1}}}
{{{(6/5)*m[2]=-1}}}
{{{m[2]=-5/6}}}
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{{{highlight(y=-(5/6)x)}}}
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{{{graph(300,300,-10,10,-10,10,0,(6/5)x-13/5,-(5/6)x)}}}