Question 373903

{{{(1 + 8i)/(-6 + i)=((1 + 8i)/(-6 + i))*((-6-i)/(-6 - i))}}}
{{{(1 + 8i)/(-6 + i)=(-6-i-48i-8i^2)/(36+6i-6i-i^2)}}}
{{{(1 + 8i)/(-6 + i)=(-6+8-49i)/(36+1)}}}
{{{(1 + 8i)/(-6 + i)=(2-49i)/(37)}}}
{{{highlight((1 + 8i)/(-6 + i)=(2/37)-(49/37)i)}}}