Question 373868
{{{2y = x^3}}}
{{{y = (1/2)*x^3}}}
and
{{{4y = x^2}}}
{{{y = (1/4)*x^2}}}
I can say
{{{(1/2)*x^3 = (1/4)*x^2}}}
Multiply both sides by {{{4}}}
{{{2x^3 = x^2}}}
Divide both sides by {{{x}}}
{{{2x = 1}}}
{{{x = 1/2}}}
and, since
{{{2y = x^3}}}
{{{2y = 1/8}}}
{{{y = 1/16}}}
and, also,
{{{4y = x^2}}}
{{{4y = 1/4}}}
{{{y = 1/16}}}
OK