Question 373837
Let {{{x}}}= ml of alcohol to be added
given:
ml of minoxidil in 10% solution:
{{{.1*60 = 6}}} ml
{{{6/(60 + x) = .09}}}
{{{6 = .09*(60 + x)}}}
{{{6 = 5.4 + .09x}}}
{{{.09x = .6}}}
{{{x = 6.667}}}
6.667 ml of alcohol need to be added 
to reduce the strength by 1%
and
{{{6/(60 + x) = .075}}}
{{{6 = .075*(60 + x)}}}
{{{6 = 4.5 + .075x}}}
{{{.075x = 1.5}}}
{{{x = 20}}}
20 ml of alcohol need to be added 
to reduce the strength by 2.5%