Question 373820
The equation becomes
{{{1/(z+2)^(2/3) = 3}}}, or
{{{1/3 = (z+2)^(2/3)}}}, or{{{1/27 = (z+2)^2}}}
{{{z+2 = 1/3sqrt(3)}}} or {{{z+2 = -1/3sqrt(3)}}} by applying the square-root principle. Therefore
{{{z= -2 + 1/3sqrt(3)}}} or{{{z = -2 -1/3sqrt(3)}}}