Question 373702
x + x+2 + x+4  =  x(x+2)-36,
{{{3x + 6 = x^2 + 2x  -36}}},
{{{0 = x^2 -x  -42}}},
0 = (x - 7)(x + 6), or x = 7.  (Eliminate x = -6)
Therefore the three consecutive odd integers are 7,9,11.