Question 5249
1. {{{(2x-3)(3x+2)}}}


2. {{{2x^3 - 3xy}}} --> {{{2(-1)^3 - 3(-1)(2)}}}
--> 2(-1) + 6
--> -2 + 6
--> 4


3. {{{12x^2-40x-32}}}=?. 


dy/dx = 24x-40

24x-40 = 0
24x = 40
x = 40/24
x = 5/3


--> y = 12(5/3)^2 - 40(5/3) - 32
so y = 12*25/9 - 200/3 - 32
y = -65 and 1/3
ie y = -196/3


So, IF you mean, what y values do you get from this function, then the answer is y>= -196/3


jon.