<PRE><B>Question 373752</B>
Consider the line  y=-2/5x+1

Find the equation of the line that is parallel to this line and passes through the point (-6,2)

Given:
Slope: m = -2/5

point: (-6,2)

y = mx + b
2 = -2(-6)/5 + b
2 = 12/5 + b
b = 2 - 12/5
b = (10-12)/5
b = -2/5

So given m = -2/5 and b = -2/5, the equation of the line is

y = -2x/5 -2/5</PRE>