Question 373666
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Given that *[tex \Large x] represents the smallest of three consecutive odd integers, the next one must be *[tex \Large x\ +\ 2] (because *[tex \Large x\ +\ 1], the next integer would be even) and the one after that is *[tex \Large (x\ +\ 2)\ +\ 2\ =\ x\ +\ 4].


Twice the smallest must be *[tex \Large 2x], so the sum of the largest plus twice the smallest is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x\ +\ 4)\ +\ 2x\ =\ 25]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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