Question 373548
Let {{{a}}} = the interest earned by both accounts
Let {{{b}}} = portion of $54000 invested at 8%
Let {{{c}}} = portion of $54000 invested at 10%
given:
{{{b + c = 54000}}}
{{{.08b = .1c}}}
{{{8b = 10c}}}
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{{{b = (5/4)*c}}}
by substitution:
{{{(5/4)*c + c = 54000}}}
{{{(9/4)*c = 54000}}}
{{{c = (4/9)*54000}}}
{{{c = 24000}}}
and
{{{b + c = 54000}}}
{{{b = 54000 - 24000}}}
{{{b = 30000}}}
$30,000 was invested at 8%
and $24,000 was invested at 10%