Question 373550
{{{4p^2 + 6p + 3 = 0}}}
{{{4p^2 + 6p = -3}}}
{{{p^2 + (3/2)*p = -3/4}}}
Take 1/2 of the coefficient of {{{p}}},
square it, and add to both sides
{{{p^2 + (3/2)*p + (3/4)^2 = -3/4 + (3/4)^2}}}
{{{(p + 3/4)^2 = 9/16 - 12/16}}}
{{{(p + 3/4)^2 = (sqrt(3)*i/4)^2}}}
{{{p + 3/4 = sqrt(3)*i/4}}}
{{{p = (-3 + sqrt(3)*i)/4}}}
and
{{{p = (-3 -sqrt(3)*i)/4}}}