Question 373395
Let them be
x and x+1
and then let us translate...
x(x+1) = 5 + x + x+1
x^2 + x = 2x + 6
now collect and factor
{{{x^2 - x - 6 = 0}}}
{{{(x - 3)(x + 2) = 0}}}
and solving we get
x = 3 and x = -2
But we need positive so throw the second solution out...
x = 3
x + 1 = 4