Question 373257
{{{4+sqrt(48)/4}}} or the {{{4+sqrt(48/4)}}}?
<p>
{{{4+sqrt(48)/4}}} find the factors of 48, 16 and 3
{{{4+sqrt(16*3)/4}}} sqrt of 16 is 4 carry 4 out
{{{4+4sqrt(3)/4}}} 4s cancel
{{{4+sqrt(3)}}}
<P>
{{{4+sqrt(48/4)}}} divide by 4
{{{4+sqrt(12)}}} factor 12
{{{4+sqrt(4*3)}}} sqrt of 4 is 2 carry it out
{{{4+2sqrt(3)}}}