Question 373122
I don't even know where to start. The problem is  log2^x = 1/3log2^27. Can you please show me step by step.


log 2^x = (1/3)log 2^27
logarithmic rule: nlogb(m) = logb(m^n)
log 2^x = log 2^(27 * 1/3)
log 2^x = log 2^9
2^x = 2^9 (these must equal)
x = 9