Question 372794
a) The angle is given as being in standard position already. Let A be the angle. Then {{{tan A = y/x = -14/3}}}.  If you're using a scientific calculator, the inverse tan key recognizes only angles coming from the interval ({{{-pi/2}}}, {{{pi/2}}}), the principal domain of tan.  Thus {{{A = tan^-1(-14/3) = -1.3597}}}.  This angle is in the 4th quadrant.  To get it back to the 2nd quadrant, add {{{pi}}} to this, which is the period of tangent.  Thus A = 1.78 radians.

b) Let A be the angle .  Then {{{tan A = y/x = 7/6}}}.  {{{A = tan^-1(7/6) = 0.86}}} radians, using a scientific calculator.  This is already in quadrant 1, so no more adjustment is needed.