Question 372984
The given equation is the same as {{{log((x-5)(x+3)) = 2}}}, or
{{{log((x^2-2x-15)) = 2}}}, or 
{{{x^2 - 2x - 15 = 10^2}}}.  Simplifying,
{{{x^2-2x - 115 = 0}}},

{{{x = (2+- sqrt((-2)^2-4*1*-115))/2) }}} ,
{{{x = (2+- sqrt(464))/2)}}},

{{{x = (2+- 4sqrt(29))/2)}}},
{{{x = 1+- 2sqrt(29)}}}.

Only the root {{{1+2sqrt(29)}}} will satisfy the original equation.