Question 372868
{{{x^2 - 9(y^2-4y) - 72 = 0}}},
{{{x^2 -9(y^2-4y + 4) + 36 - 72 = 0}}},
{{{x^2 - 9(y-2)^2 - 36 = 0}}},
{{{x^2 - 9(y-2)^2 = 36}}},
{{{x^2/36 - (y-2)^2/4 = 1}}},
it's an hyperbola with vertex at (0,2), y-axis as the conjugate axis and y = 2 as the transverse axis.