Question 372777
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He can do 3/4 of an 8 m radius circle, plus 2 quarters (1/2) of a 2 m radius circle.  Hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ \frac{3}{4}\,\cdot\,64\pi\ +\ \frac{1}{2}\,\cdot\,4\pi\ =\ 48\pi\ +\ 2\pi\ =\ 50\pi\text{ m^2}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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