Question 372754
<font face="Garamond" size="+2">

So far, perfect.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (m\,-\,k)(x)\ =\ (6x\ -\ 9)\ -\ \frac{2\ -\ 3x}{6x}]


The common denominator is *[tex \Large 6x], so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (m\,-\,k)(x)\ =\ \frac{6x(6x\ -\ 9)\ -\ (2\ -\ 3x)}{6x}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (m\,-\,k)(x)\ =\ \frac{36x^2\ -\ 54x\ -\ 2\ +\ 3x}{6x}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (m\,-\,k)(x)\ =\ \frac{36x^2\ -\ 51x\ -\ 2}{6x}]


And that is all there is.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
<div style="text-align:center"><a href="http://outcampaign.org/" target="_blank"><img src="http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png" border="0" alt="The Out Campaign: Scarlet Letter of Atheism" width="143" height="122" /></a></div>
</font>