Question 372610
1.{{{x^2+y=9}}}
2.{{{x-y+3=0}}}
Add eq. 1 to eq. 2,
{{{x^2+y+x-y+3=9}}}
{{{x^2+x+3=9}}}
{{{x^2+x-6=0}}}
{{{(x+3)(x-2)=0}}}
Two solutions:
{{{x+3=0}}}
{{{highlight(x=-3)}}}
Then from eq. 2,
{{{-3-y+3=0}}}
{{{highlight(y=0)}}}

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{{{x-2=0}}}
{{{highlight_green(x=2)}}}
Then from eq. 2,
{{{2-y+3=0}}}
{{{highlight_green(y=5)}}}
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{{{drawing( 300, 300, -8, 8, -4, 12,grid(1),
circle(-3,0,0.3),
circle(2,5,0.3),graph( 300, 300, -8, 8, -4, 12, 0,x+3, 9-x^2)) }}}