Question 372613
Use a substitution,
{{{u=e^x}}}
{{{u^2=e^(2x)}}}
{{{u^2-9u+14=0}}}
{{{(u-2)(u-7)=0}}}
Two solutions:
{{{u-2=0}}}
{{{u=2}}}
{{{e^x=2}}}
{{{highlight(x=ln(2))}}}
.
.
.
{{{u-7=0}}}
{{{u=7}}}
{{{highlight(x=ln(7))}}}