Question 372743
{{{(49n^(-10))^(-1/2)*n^5=n^5/sqrt(49n^(-10))}}}
{{{(49n^(-10))^(-1/2)*n^5=n^5/(7n^(-5))}}}
{{{(49n^(-10))^(-1/2)*n^5=(1/7)n^(5-(-5))}}}

{{{(49n^(-10))^(-1/2)*n^5=highlight(n^10/7))}}}