Question 372647
the LCD of x-1 and x+1 is (x+1)(x-1)=(x^2-1)
 
Domain of definition x is not 1 or -1.
 

{{{ x/(x+1)-1/(x-1)=2/(x^2-1)}}} times (x^2-1)=(x+1)(x-1)

x(x-1) - (x+1) = 2
 
x^2-x-x-1 = 2
 
x^2 -2x -3 = 0
 
(x-3)(x+1)=0
 
the solutions are : x=3 or x=-1, x=-1 is no solution since it would be a division by zero)
 
Solution : x=3
 
Verification : 3/4 - 1/2 = 1/4
 
and RHS : 2/(9-1)=2/8=1/4, which is the same.