Question 41086
Let the slower car travel at a rate of r.  The faster travels at a rate of r+10.
We always use rate*time = distance in these travel problems.
Here their combined distance after 3 hours is 330 miles...so
3r + 3(r+10) = 330
3r + 3r + 30 = 330
6r + 30 = 330
6r = 300
r = 50
r+10 = 60