Question 372725
{{{y=x^2-4x+4}}}
{{{y=(x-2)^2}}}
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To find the x-intercept, set {{{y=0}}} and solve for {{{x}}}.
{{{y=(x-2)^2}}}
{{{y=(x-2)^2=0}}}
{{{x-2=0}}}
{{{x=2}}}
({{{2}}},{{{0}}})
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To find the y-intercept, set {{{x=0}}} and solve for {{{y}}}.
{{{y=(x-2)^2}}}
{{{y=(0-2)^2}}}
{{{y=4}}}
({{{0}}},{{{4}}})
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{{{drawing(300,300,-5,5,-5,5,grid(1),circle(0,4,0.2),circle(2,0,0.2),graph(300,300,-5,5,-5,5,0,(x-2)^2))}}}