Question 372724
Complete the square in {{{x}}} and {{{y}}}.
{{{x^2+y^2+12x+8y+16=0}}}
{{{(x^2+12x+36)+(y^2+8y+16)+16=36+16}}}
{{{(x+6)^2+(y+4)^2=36}}}
Compare to the general equation for a circle centered at ({{{h}}},{{{k}}}) with a radius {{{R}}}:
{{{(x-h)^2+(y-k)^2=R^2}}}