Question 372692
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Hi,
Note: The probability of x successes in n trials is: 
P = nCx* {{{p^x*q^(n-x)}}} where p and q are the probabilities of success and failure respectively. 
In this case p = .13 , q = .87  and n = 5 
nCx = {{{n!/(x!(n-x!))}}}
P(at least 3 of the five eliminated jobs) = 1 - P(0) -P(1) -P(2)
P(0) = .4984  (.87)^5
P(1) = .3724  5*(.13)^1(.87)^4
P(2) = .1113  10*(.13)^2(.87)^3

P(at least 3 of the five eliminated jobs) = 1 - .9821 = .0179