Question 372701
Complete the square in {{{x}}} and {{{y}}}.
{{{x^2+y^2+12x+4y+76=0}}}
{{{(x^2+12x+36)+(y^2+4y+4)+76=36+4}}}
{{{(x+6)^2+(y+2)^2=40-76}}}
{{{(x+6)^2+(y+2)^2=-36}}}
Compare this equation to the general equation of a circle centered at (h,k) with a radius R.
{{{(x-h)^2+(y-k)^2=R^2}}}
In this case, your equation is not the equation for a circle.