Question 372652
Use the law of exponents,
{{{(18xy^3)/(96x^2y^3)=(18/96)x^(1-2)y^(3-3)}}}
{{{(18xy^3)/(96x^2y^3)=(3/16)x^(-1)y^(0)}}}
{{{(18xy^3)/(96x^2y^3)=highlight(3/(16x))}}}