Question 372551
Use the common denominator, {{{2(y-3)=2y-6}}}
{{{5/(y-3) = 1 + (y+7)/(2y-6)}}}
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{{{10/(2y-6)=(2y-6)/(2y-6)+(y+7)/(2y-6)}}}
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{{{(10-(2y-6)-(y+7))/(2y-6)=0}}}
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{{{(10-2y+6-y-7)/(2y-6)=0}}}
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{{{(-3y+9)/(2y-6)=0}}}
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{{{(-3(y-3))/(2(y-3))=0}}}
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{{{-3/2=0}}}
Since the equation leads to an inconsistency, there is no solution.