Question 372527
{{{ -4x+2y>=6 }}}
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Graph the line,
{{{-4x+2y=6}}}
{{{2y=4x+6}}}
{{{y=2x+3}}}
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{{{graph(300,300,-10,10,-10,10,2x+3)}}}
The graph breaks the plane into two regions.
Choose a point in either region (not on the line).
Test the inequality. 
If the inequality is satisifed, shade the region that includes the test point.
If it's not, shade the region that doesn't include the test point.
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({{{0}}},{{{0}}}) is a convenient point.

{{{-4x+2y>=6}}}
{{{-4(0)+2(0)>=6}}}
{{{0>=6}}}
False, so shade the region that doesn't contain ({{{0}}},{{{0}}}).
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*[invoke plot_any_inequality "-4x+2y>=6", -10, 10, -10, 10, 300, 300]
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Additionally, since the inequality includes the "=" sign, the line is also part of the solution.