Question 372526
Work the problem backwards.
Find the probability that the card is an ace.
{{{P(A)=4/52=1/13}}}
Find the probability that the card is a heart.
{{{P(H)=13/52=1/4}}}
Remember to subtract the ace of hearts so you don't double count,
So the probability that the card is either a heart or an ace is,
{{{P=P(A)+P(H)-1/52=4/52+13/52-1/52=16/52=4/13}}}
The probability that is neither a heart nor an ace is that probability subtracted from 1.
{{{P=13/13-4/13}}}
{{{highlight(P=9/13)}}}