Question 372487
I need to use quadratic equations to find two real numbers that satisfy the sum of 15 and the product 36

Let x = the 1st number
    y = the 2nd number

x+y = 15
xy  = 36
  y = 36/x

x+36/x = 15
multiply both sides by x
x^2+36 = 15x
x^2-15x+36 = 0
(x-3)(x-12) = 0
x = 3
y = 12

The numbers are 3 and 12