Question 372487
x+y =15
xy = 36
x= 36/y
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plug value of x in the first equation
36/y +y =15
(36+y^2)/y =15
36+y^2 =15y
y^2-15y+36=0
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y^2-12x-3x+36=0
y(y-12)-3(y-12)=0
(y-12)(y-3)=0
y =12 OR y =3
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