Question 5224
you can work this out from this starting point if you are OK with working with  powers. If not, a very acceptable solution is to say the following:


Let y = {{{sqrt(x)}}} --> so {{{y^2 = x}}}


Therefore the equation then becomes {{{y^2 + 8y = 0}}} which can be factorised to y(y+8) = 0


So either y=0 or y+8 = 0
So, y=0 or y = -8. 

y is a square root, which cannot be negative, so -8 is not a possible solution. 


Hence, {{{sqrt(x) = 0}}}


Squaring sqrt(x) = 0 gives x=0


jon.