Question 372260
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (g\ -\ h)(x)\ =\ g(x)\ -\ h(x)\ =\ (x\ -\ 4)\ -\ (4x\ +\ 2)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (g\ \cdot\ h)(x)\ =\ g(x)\ \cdot\ h(x)\ =\ (x\ -\ 4)(4x\ +\ 2)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (g\ +\ h)(x)\ =\ g(x)\ +\ h(x)\ =\ (x\ -\ 4)\ +\ (4x\ +\ 2)]


You get to simplify these yourself.


Once you simplify the last one, substitute -2 for *[tex \Large x] and do the arithmetic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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