Question 372234
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Let *[tex \Large x] be the original 10s digit and let *[tex \Large y] be the original 1s digit.


First we are given that:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ y\ =\ 14]


And then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 10x\ +\ y\ -\ 18\ =\ 10y\ +\ x]


Collecting terms:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 9x\ -\ 9y\ =\ 18]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ -\ y\ =\ 2]


So solve the system:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ y\ =\ 14]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ -\ y\ =\ 2]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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