Question 41090
FIRST PART:
Let the angle be {{{x^o}}}.
Then, its supplement = {{{(180 - x)^o}}}
Its complement = {{{(90 - x)^o}}}; twice the complement = {{{2*(90 - x)^o}}}
By problem,
{{{(180 - x) - 2*(90 - x) = 10}}}
or {{{180 - x - 180 + 2x) = 10}}}
or x = 10


Ans: The reqd. angle is 10 degrees.



SECOND PART:
Let the numbers be (n-2), (n-1), n, (n+1) and (n+2).
Their sum = (n-2) + (n-1) + n + (n+1) + (n+2) = 5n = 0 (given)
So n = 0.


Ans: The integers are -2, -1, 0, 1 and 2.