Question 372186
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Depends.


Do you mean what I think you mean, namely:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{3}{4}x\ =\ \frac{1}{2}\ +\ \frac{2}{3}x]?


Or do you mean what you wrote:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{3}{4x}\ =\ \frac{1}{2}\ +\ \frac{2}{3x}]?


Re-post using parentheses to eliminate ambiguity and misunderstanding.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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