Question 372030
Let A be the amount of 14% alloy.
Let B be the amount of 25% alloy.
1.{{{A+B=77}}}
.
.
{{{14A+25B=17(77)}}}
2.{{{14A+25B=1309}}}
Multiply eq. 1 by (-14) and add to eq. 2,
{{{-14A-14B+14A+25B=-1078+1309}}}
{{{11B=231}}}
{{{highlight(B=21)}}}ounces
Then from eq. 1,
{{{A+21=77}}}
{{{highlight(A=56)}}}ounces