Question 371963
  <pre><font size = 3 color = "indigo"><b>
Hi,
y=-2x+2  line contains points (a, 8) and (5, b)
{{{m =(y[2] - y[1])/(x[2] - x[1])}}}
(a, 8) and (5, b)
{{{((b-8)/(5-a)) = (-2/1)}}}
cross multiplying
-2(5-a) = (b-8)
-10 + 2a + 8 = b
2a - 2 = b
y=-2x+2   Using ordered pair(5,b)
b = -2*5 + 2   
Substituting for b
2a - 2 = -2*5 + 2
2a - 2 = -8
2a = -6
a = -3  and b is -8 (2*-3 - 2)
(-3, 8) and (5, -8)
{{{drawing(300,300, -10, 10, -10, 10,grid(1),
circle(-3, 8,0.3),
circle(5, -8,0.3),
graph( 300, 300, -10, 10, -10, 10, -2x+2))}}}