Question 371962
Use "*" to signify multiplication and use parentheses, they're free.
I think this is what you mean,
((x^2+3x+2)*(x^3y^3))/((x^2y^4)*(x^2+2x+1))  ={{{((x^2+3x+2)*(x^3y^3))/((x^2y^4)*(x^2+2x+1)) }}}
If not, please repost.
{{{((x^2+3x+2)*(x^3y^3))/((x^2y^4)*(x^2+2x+1))=((x+1)(x+2)x^3y^3)/(x^2y^4(x+1)^2) }}}
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{{{((x^2+3x+2)*(x^3y^3))/((x^2y^4)*(x^2+2x+1))=highlight((x(x+2))/(y(x+1))) }}}