Question 371956
  <pre><font size = 3 color = "indigo"><b>
Hi,
f(x)=-16x^2+8x+3
f(x)=-16[x^2+(1/2)x -3/16}
f(x)=-16[(x-1/4)^2 - 1/16 -3/16}
f(x)=-16(x-1/4)^2 + 4
x intercepts (y=0)
0 = -16(x-1/4)^2 + 4
-4/-16 = (x-1/4)^2  taking the square root of both sides of the equation
+-2/4 = x - 1/4
1/4 +- 1/2 = x
-1/4 = x
3/4 = x
y intercept (x=0)
y = -16(-1/4)^2 + 4
y = -1 + 4 = 3
{{{drawing(300,300, -6, 6, -6, 6, grid(1),
graph( 300, 300,-6,6,-6,6,-16(x-1/4)^2 + 4)) }}}