Question 371924
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Hi,
Write an equation line containing Pt(-7,2) and parallel to the line 8x=3y+7

*Note: The standard point-slope form for an equation of a line y = mx + b  
where m is the slope and b the y-intercept.  
8x=3y+7    Solving for y to put this equation into the slope-intercept form
8x - 7 = 3y
(8/3)x -(7/3) = y
Slope is (8/3)   Parellel lines have equal slopes
New line:
y = (8/3)x + b   Using ordered pair(-7,2) to solve for b
2 = (8/3)*(-7) + b  
6/3 +(56/3) = b
62/3 = b
the equation of the line containing Pt(-7,2) and parallel to the line 8x=3y+7
y = (8/3)x + 62/3
{{{drawing(300,300, -25, 25, -25, 25,  grid(1),
circle(-7, 2,0.5),
graph( 300, 300,  -25, 25, -25, 25,(8/3)x +(62/3)))}}}