Question 371923
1st Red:{{{P(R)=26/52=1/2}}}
2nd Red:{{{P(R)=25/51}}}
{{{P(R,R)=(1/2)(25/51)}}}
{{{P(R,R)=25/102}}}
Since there are the same number of reds and blacks.
{{{P(B,B)=25/102}}}
So the probability that the cards are the same color is,
{{{P=P(R,R)+P(B,B)}}}
{{{P=25/102+25/102}}}
{{{highlight(P=25/51)}}}