Question 371911
{{{(y^2+6y+6)-(y^2-3y+8)=(y^2-y^2)+(6y-(-3y))+(6-8)}}}
{{{(y^2+6y+6)-(y^2-3y+8)=(0)+(6y+3y)+(-2)}}}
{{{(y^2+6y+6)-(y^2-3y+8)=highlight(9y-2)}}}