Question 41021
I LOVE infinite series.
ok so 1+1/5+1/25+1/125+1/625...
1+.2+.04+.008+.0016
or 1+(1*2)/10+(1*4)/100+(1*8)/1000...
or 1+...
we have 1/5+1/25=6/25+1/125=31/125+1/625=156/625 and so on
so y={{{(((((1*5+1)*5+1)*5+1)*5+1)*5+1)}}}
or, ignoring the order of whatever its called,
we add one and multiply by 5 over and over again, infinitely, over
0+1*5+1*5+1*5...
_____________
5(5)(5)(5)(5)
yielding {{{(((((0+1)5+1)5+1)5+1)5+1)5...)/5*5*5*5*5...}}}
or {{{((0+1)/5)*(125/6)}}}

ok forget all of that, a lot of it is wrong.  But be ready to refer to it.  don't worry if it made no sense.

now im very sorry, i feel quite childish in terms of intellect; perhaps you can solve it from here..
I got {{{E(x/5^x)}}} ...:P I can't solve it anymore!

I do, however, feel like much less of a mathematical amateur telling you that the answer is obviously, of the four choices listed above, 5/4, because its the only number higher than one, and seeing as how this infinite series is 1+ something.. well, you can make the connection:)

I would REALLY appreciate it if you could perhaps teach me by way of email how to get the solution when you do

yours truly, <-)))><mszlmb><(((->
<hl>
<b>sorry about all that, i worked on it today..here's what iv come up with..</b>
<center>so we have 1+.2+.04+.008 etc.<br>Do you see the pattern, again, of *2 and *5?</center>
<center>This can be expressed as {{{2^x/10^x}}}.  That's to get any the xth number (ie the 5th number is 32/100000, or .000032; try it.)</center>
<center>Of course, this is not what we want, we want {{{E[N]x}}} when {{{f(x)=2^x/10^x}}}; E, representing sigma, means the addition of all of the following.  By E[N] I mean sigma of all N, positive integers.  (E[n]{1,2,3.4,5}=8)
we're basically looking for all solutions for {{{2^x/10^x}}} given x=N (positive integer).
this can also be expressed as E[n]{{{1^x/5^x}}}; I can simplify it no further as of now.

Again, it is obvious the answer is 5/4 because it is the only choice over 1, an easy choice considering the question is 1+something.
I checked, and it really does equal 5/4; I just can't find how to get there :P
good luck and if u get the process email me ;)