<PRE><B>Question 371024</B>

2 is 2 times and 3 is 3 times repeated in given digits.


a)  no. of ways to form 7 digit no. = 7! / ( 2! * 3!) = 420


 no. of ways to form 7 digit no. having 0 at starting place = 6!/(2! * 3!) = 60

( here we have to arrange remaining 6 digits only because 0 at fixed position )


so, total no. that not start with 0 =  420-60 = 360 



b)similarly to last solution


no. of ways to form 7 digit no. having  0 at last place = 6!/(2! * 3!)




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